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7p^2-7p=210
We move all terms to the left:
7p^2-7p-(210)=0
a = 7; b = -7; c = -210;
Δ = b2-4ac
Δ = -72-4·7·(-210)
Δ = 5929
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{5929}=77$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7)-77}{2*7}=\frac{-70}{14} =-5 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7)+77}{2*7}=\frac{84}{14} =6 $
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